Question

If an electron in hydrogen atom jumps from an orbit of level n = 3 to an orbit of level n = 2, then emitted radiation has a frequency equal to,

• A. $\frac{3Rc}{27}$
• B. $\frac{Rc}{25}$
• C. $\frac{8Rc}{9}$
• D. $\frac{5Rc}{36}$

Answer 1

The correct option is D

$\frac{5Rc}{36}$

$\frac{1}{\lambda }=R[\frac{1}{n_2^2}-\frac{1}{n_1^2}]\frac{1}{\lambda }=R[\frac{1}{(2{)}^2}-\frac{1}{(3{)}^2}]\frac{1}{\lambda }=R[\frac{1}{4}-\frac{1}{9}]=\frac{5R}{36}f=\frac{c}{\lambda }f=c\times \frac{5R}{36}=\frac{5Rc}{36}$