Question

If an electron is revolving in a circular orbit of radius $0.5A^o$ with a velocity of $2.2\times {10}^{6}m/s$. The magnetic dipole moment of the revolving electron is (Charge on electron $e=1.6\times {10}^{-19}$)

• A. $8.8\times {10}^{-24}Am$
• B. $8.8\times {10}^{-23}Am$
• C. $8.8\times {10}^{-22}Am$
• D. $8.8\times {10}^{-21}Am$

Answer 1

The correct option is A $8.8\times {10}^{-24}Am$

$r=0.5A^{o}V=2.2\times {10}^{6}m{s}^{-1}$
$\mu$ = $i.A$
$=ef.Ar2$
$=\frac{ew}{2a}.A{r}^2$
$=\frac{ev{r}^2}{2r}$
$=\frac{evr}{2}$
$=\frac{1.6\times {10}^{-19}\times 2.2\times {10}^6\times 0.5\times {10}^{-10}}{2}$
$=8.8\times$${10}^{-24}Am$