Question

If an electron of hydrogen atom jumps from $n=4$ to $n=2$. Calculate the energy emitted?

Answer 1

Energy of an electron is given by: $E_n=\frac{13.6\times z}{n^2}eV$

Energy emitted = (Energy of electron in n=2) - (Energy of electron in n=4)

$⟹$ Energy emitted = $\frac{13.6\times 1}{2^2}-\frac{13.6\times 1}{4^2}eV$

$⟹$ Energy emitted = $2.55eV$