Question

If an electron revolving in $n^{th}$ excited state orbit with $1090km/s$ in $L{i}^{+2}$ ion then find max find max possible spectral lines for the electron transition from the same excited state to find excited state.

• A. $3$
• B. $5$
• C. $4$
• D. $6$

Answer 1

The correct option is B $5$

$V=\frac{2.18\times {10}^{6}z}{n}㎧=2180\frac{z}{n}㎞/s$

$\therefore 1090=\frac{2180\times 3}{n}\Rightarrow n=6$

Max lines in exciting electron to $n^{th}$ state $=n-1=6-1=5$

Hence answer is option B.