If an element X exists in its two isotopic form 35 17X 75- and 37 17X 25- The average atomic mass of element X is-

Contribution of isotope nbsp;^35 _17X to the atomic mass of X =35 ×75100=26.25 u Contribution of isotope nbsp;^37 _17X to the atomic mass of X =37 ×25100=9. ...

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Standard XII

Chemistry

Atoms and Molecules

If an element...

Question

If an element $X$ exists in its two isotopic form $_{17}^{35} X (75 %)$ and $_{17}^{37} X (25 %)$ . The average atomic mass of element $X$ is:

36 u

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36.5 u

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35.5 u

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None of these

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Solution

The correct option is C $35.5 u$
Contribution of isotope $_{17}^{35} X$ to the atomic mass of $X$ $= 35 \times \frac{75}{100} = 26.25 u$
Contribution of isotope $_{17}^{37} X$ to the atomic mass of $X$ $= 37 \times \frac{25}{100} = 9.25 u$
Hence average atomic mass of $X = 26.25 u + 9.25 u = 35.5 u$

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If an element X exists in its two isotopic form 3517X (75%) and 3717X (25%). The average atomic mass of element X is:

The correct option is C 35.5 uContribution of isotope 3517X to the atomic mass of X =35×75100=26.25 u Contribution of isotope 3717X to the atomic mass of X =37×25100=9.25 u Hence average atomic mass of X=26.25 u+9.25 u=35.5 u

If an element $X$ exists in its two isotopic form $_{17}^{35} X (75 %)$ and $_{17}^{37} X (25 %)$ . The average atomic mass of element $X$ is: