If an element X is placed in group 14, the formula its chloride is:

X C l

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X C l_{2}

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X C l_{3}

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X C l_{4}

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Solution

The correct option is D $X C l_{4}$
As it is in group 14 it will have 4 electrons in the outer most shell. Hence it can share 4 electrons with 4 chlorine's because each chlorine can share only one electron. $X C l_{4}$ it forms this compound. Here as we mentioned that it shares because it cannot donate or accept 4 electrons rather than sharing is far better than that. Hence it is a covalent bond.

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