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Question
If an endothermic reaction is non-spontaneous at freezing point of water and becomes feasible at its boiling point, then:
If an endothermic reaction is non-spontaneous at freezing point of water and becomes feasible at its boiling point, then:
H is -ve, 
S is +ve
H and 
S both are +ve
H and 
S both are -ve
H is +ve, 
S is -ve
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Solution
The correct option is B H and S both are +ve
△G = △H - T△S, since △G = +ve at T = 273 K and △H = +ve and high temperature 373 K, it becomes spontaneous (△G = -ve) even if △H = +ve. This is a possible only if △S = +ve because at high temperature. T△S >△H to give △G = -ve.
H and S both are +ve
△G = △H - T△S, since △G = +ve at T = 273 K and △H = +ve and high temperature 373 K, it becomes spontaneous (△G = -ve) even if △H = +ve. This is a possible only if △S = +ve because at high temperature. T△S >△H to give △G = -ve.
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