Question

If an incident ray is directed towards a corner reflector as shown, at what angle$\left(\theta \right)$ does the reflected ray emerge?

• A. ${22}^{\circ }$
• B. ${68}^{\circ }$
• C. ${44}^{\circ }$
• D. ${46}^{\circ }$

Answer 1

The correct option is B ${68}^{\circ }$


From figure,
Angle of incidence, $\angle i={90}^{\circ }-{22}^{\circ }={68}^{\circ }$
$\angle i=\angle r={68}^{\circ }$
Since $N_1\perp N_2$,
$\angle r+\angle \alpha ={90}^{\circ }$
$\Rightarrow \angle \alpha ={90}^{\circ }-{68}^{\circ }={22}^{\circ }$
$\therefore \theta =90-\alpha ={68}^{\circ }$
Hence, option $\left(b\right)$ is the correct answer.