If an incident ray is directed towards a corner reflector as shown, at what angle(θ) does the reflected ray emerge?
A
22∘
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B
68∘
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C
44∘
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D
46∘
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Solution
The correct option is B68∘
From figure,
Angle of incidence, ∠i=90∘−22∘=68∘ ∠i=∠r=68∘
Since N1⊥N2, ∠r+∠α=90∘ ⇒∠α=90∘−68∘=22∘ ∴θ=90−α=68∘
Hence, option (b) is the correct answer.