If an increase in length of copper wire is 0.5% due to stretching, the percentage increase in its resistance will be

0.1 %

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0. 2%

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Solution

The correct option is C 1%
Resistance of the wire $R = \frac{ρ L^{2}}{V}$ where $V$ and $ρ$ are constants
$∴$ Percentage increase in resistance $= \frac{Δ R}{R} \times 100 = \frac{2 Δ L}{L} \times 100$
Given : $\frac{Δ L}{L} \times 100 = 0.5$
$⟹$ Percentage increase in resistance $= 2 \times 0.5 = 1$ %

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If an increase in length of copper wire is 0.5% due to stretching, the percentage increase in its resistance will be

The correct option is C 1%Resistance of the wire R=ρL2V where V and ρ are constants∴ Percentage increase in resistance =ΔRR×100=2ΔLL×100Given : ΔLL×100=0.5⟹ Percentage increase in resistance=2×0.5=1 %