If an integer is chosen at random and squared, then the probability that the last digit of the square is either 1 or 5, is
A
310
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B
25
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C
15
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D
12
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Solution
The correct option is A310 Last digit of any integer can be 0,1,2,3,4,5,6,7,8,9 ∴n(S)=10
Let A be the event that the last digit of square is either 1 or 5.
It will be 1 or 5 only when the last digit of integer is 1,5 or 9. ∴n(A)=3 ⇒P(A)=n(A)n(S)=310