Question

If an ion of ${}_{25}$Mn has a magnetic moment of 3.873 B.M. Then which state $Mn$ is?

• A. 2
• B. 3
• C. 4
• D. 5

Answer 1

The correct option is C 4

Here, $\sqrt{n(n+2)}=3.873B.M.$.
So $n=3$.
E.C. of $M{n}^{4+}=1s^2,2s^2,2p^6,3s^2,3p^6,3d^3$.
So, 3 unpaired electrons in $M{n}^{4+}$.