If an object has rotational symmetry of order $5$ ,what will be its angle of rotation?

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Solution

We know that if the order of rotational symmetry is $x$ then the angle of rotation will be = $\frac{360 °}{x}$
As we have given the order of symmetry is $5$ .
Using the above formula we get:
The angle of rotation is = $\frac{360 °}{5}$
The angle of rotation is = $72 °$
Hence, the angle of rotation is $72 °$ .

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If an object has rotational symmetry of order 5,what will be its angle of rotation?

We know that if the order of rotational symmetry is x then the angle of rotation will be = 360°xAs we have given the order of symmetry is 5.Using the above formula we get:The angle of rotation is = 360°5The angle of rotation is = 72°Hence, the angle of rotation is 72°.

If an object has rotational symmetry of order $5$ ,what will be its angle of rotation?