Question

If an object is thrown horizontally with an initial speed 10 M per second from the top of the building of height hundred metre. what is horizontal distance covered by the particle?

Answer 1

This is the case of horizontal projectile.
Given, initial velocity , u = 10m/s
height , h = 100m
use the formula,
Horizontal range , X = u√(2h/g)
So, X = 10 × √{2 × 100/9.81}
X = 45.15 m

Hence, horizontal distance covered by object is 45.15 m.

If g= 10m/ s^2

This is the case of horizontal projectile.
Given, initial velocity , u = 10 m/s
height , h = 100m
use the formula,
Horizontal range , X = u√(2h/g)
So, X = 10 × √{2 × 100/10}
X = 10 × √20 m

Hence, horizontal distance covered by object is 10√20 m