If an object travels at a speed of $20 m s^{- 1}$ for the first $2 s e c o n d s$ and $30 m s^{- 1}$ for the next 3 seconds, what is the total distance travelled?

100 m

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150 m

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130 m

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60 m

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Solution

The correct option is C $130 m$
Given:
Speed in the first $2 s e c o n d s$ = $20 m s^{- 1}$
Distance travelled = speed $\times$ time = $20 \times 2 = 40 m$

Speed in the next $3 s e c o n d s$ = $30 m s^{- 1}$
Distance travelled = $30 \times 3 = 90 m$

$∴$ Total distance travelled $= 40 + 90 = 130 m$

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