If ∠APB=60∘ and with B as the centre and any radius more than half of AB, another arc is drawn as shown. Taking A as the centre and the same radius as above, cut the previously drawn arc in Y and PY is drawn.
What will be the value of ∠BPY?
A
30∘
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B
60∘
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C
90∘
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D
180∘
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Solution
The correct option is A
30∘
From the given construction, we get PY as the angle bisector of ∠APB.
Therefore ∠BPY=∠APY=602=30∘.