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B
40∘
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C
160∘
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D
∠COB
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Solution
The correct options are A∠CBD B40∘ Since the angle subtended by an arc at the centre of a circle is double the angle subtended by it at any remaining point on the circle, we have ∠COD=2×∠CAD. Also, ∠COD=2×∠CBD. Thus, ∠CAD=∠CBD=80∘2=40∘.