If angle of minimum deviation through an equilateral prism is $40^{o}$ , angle of incidence (being equal to angle of emergence) would be

50^{o}

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60^{o}

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40^{o}

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none of these

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Solution

The correct option is A $50^{o}$
For minimum deviation $i = e i = e$
$a + δ m = i + e a + δ m = i + e$
$a + δ m = 2 i a + δ m = 2 i$
$60^{o} + 40^{o} = 2 i$
$i = 50^{o}$

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If angle of minimum deviation through an equilateral prism is 40o, angle of incidence (being equal to angle of emergence) would be

The correct option is A 50oFor minimum deviation i=ei=ea+δm=i+ea+δm=i+ea+δm=2ia+δm=2i60o+40o=2ii=50o

If angle of minimum deviation through an equilateral prism is $40^{o}$ , angle of incidence (being equal to angle of emergence) would be

The correct option is A $50^{o}$
For minimum deviation $i = e i = e$
$a + δ m = i + e a + δ m = i + e$
$a + δ m = 2 i a + δ m = 2 i$
$60^{o} + 40^{o} = 2 i$
$i = 50^{o}$