Question

If angular displacement of a particle is given by $\theta =a-bt+c{t}^2$ then find its angular velocity

• A. $-b+2ct$
• B. $b-2ct$
• C. $2b-ct$
• D. $b+2ct$

Answer 1

The correct option is A $-b+2ct$

Answer is A.

The angular velocity is given as $\omega =\frac{d\theta }{dt}$.
It is given that $\theta =a-bt+c{t}^2$.
So, $\omega =\frac{d(a-bt+c{t}^2)}{dt}=-b+2ct$.
Hence, the angular velocity is $-b+2ct$.