Question

If angular velocity of a disc depends on an angle rotated as $\omega =({\theta }^2+\theta ),$ then its angular acceleration at $\theta =1$ rad is:-

• A. $3rad/s^2$
• B. $6rad/s^2$
• C. $2rad/s^2$
• D. $9rad/s^2$

Answer 1

The correct option is

A

$6rad/s^2$

Given that angular velocity of a disc depends on an angle rotated as $\omega =({\theta }^2+\theta ),$

So angular acceleration = $\alpha =\omega \frac{d\omega }{d\theta }=({\theta }^2+\theta )(2\theta +1)$

At $\theta =1rad,\alpha =6rad/s^2$