If any point $P (x, y)$ satisfies the relation represents parabola, then
$(5 x - 1)^{2} + (5 y - 2)^{2} = λ (3 x - 4 y - 1)^{2}$

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Solution

The correct option is A =1
Conceptual

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Similar questions

(5 x - 1)^{2} + (5 y - 2)^{2} = (λ^{2} - 2 λ + 1) (3 x + 4 y - 1)^{2}

\sqrt{(x - 1)^{2} + (y - 2)^{2}} = \sqrt{λ} | x + y + 3 |

x^{3} - 5 x^{2} + 4 x + λ = 0

λ \neq 1

λ \neq 2

λ \neq - 1

λ \neq 0

\sqrt{(x - 1)^{2} + (y - 2)^{2}} = \sqrt{λ} | x + y + 3 |

λ x^{2} + 4 y + y^{2} + λ x + 3 y + 2 = 0

λ

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