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Question

If AP bisects BAC and M is any point on AP then the perpendiculars drawn from M to AB and AC are equal.
State whether the above statement is true or false.

A
True
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B
False
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Solution

The correct option is A True
Given: ABC, AP bisects BAC, MQAB,MNAC
In AMQ and AMN
AM=AM (Common)
MAQ=MAN (AP bisects A)
MQA=MNA (Each 90)
thus, AQMANM (ASA rule)
Hence, MQ=MN
Perpendicula and rs from M on AB and AC are equal

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