If APB and CQD are parallel lines and a transversal PQ cut them at P and Q, then the bisectors of angles APQ, BPQ, CQP and PQD form a

Rectangle

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Square

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Any other parallelogram

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Rhombus

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Solution

The correct option is A
Rectangle

Rectangle PQRS is formed by the bisectors of angles APQ, BPQ, CQP and PQD.

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∠ A P Q, ∠ B P Q, ∠ C Q P

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∠ P T Q = 90^{o}

If $A P B$ and $C Q D$ are two parallel lines then the bisectors of $∠ A P Q, ∠ B P Q, ∠ C Q P a n d ∠ P Q D$ enclose a

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(b) rhombus

(d) kite

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