Question

If arav has 'x' number of apples and vimal has five more than twice the number of apples arav has, then the total number of apples with arav and vimal is algebraically written as

• A. x + (3 + 2x)
• B. x + (5 + 2x)
• C. x - (2 + 3x)
• D. 9 + (3 + 2x)

Answer 1

The correct option is B

x + (5 + 2x)

Given arav has 'x' number of apples.

Then 'twice the number of apples arav has' is algebraically written as '2x' and hence ' vimal has five more than twice the number of apples arav has' is algebraically written as '5+2x'.

Thus the total number of apples with arav and vimal is given by the sum of the number of apples with arav and the number of apples with vimal.

So, the total number of apples with arav and vimal is algebraically written as 'x+5+2x'.