Question

If arc AXB and arc AYB are corresponding arcs and m(arc AXB) = 120${}^{\circ }$ then m(arc AYB) =

• A. ${140}^{\circ }$
• B. ${60}^{\circ }$
• C. ${240}^{\circ }$
• D. ${160}^{\circ }$

Answer 1

The correct option is C ${240}^{\circ }$

Consider that arc AXB is the minor arc and arc AYB is the corresponding major arc. It is known that, measure of major arc = ${360}^{\circ }$ − measure of the corresponding minor arc.

We have, m(arc AXB) = ${120}^{\circ }$ .

So, m(arc AYB) = ${360}^{\circ }$ − m(arc AXB) = ${360}^{\circ }-{120}^{\circ }={240}^{\circ }$