Question

If α, β, γ are the zeros of the polynomial 2x³ + x² − 13x + 6, then αβγ = ?

(a) −3
(b) 3
(c) $\frac{-1}{2}$
(d) $\frac{-13}{2}$

Answer 1

$$\begin{gathered} \left(\text{a}\right)-3 \\ \text{Since}\mathrm{\alpha }\text{,}\mathrm{\beta }\mathrm{and}\mathrm{\gamma }\text{are the zeroes of}2x^3+x^2-13x+6,\text{we have:} \\ \mathrm{\alpha \beta \gamma }=\frac{-\left(\text{constant term}\right)}{\text{co-efficient of}{x}^3}=\frac{-6}{2}=-3 \end{gathered}$$