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Question

If α, β are the zeros of the polynomial (x2 − x − 12), then form a quadratic equation whose zeros are 2α and 2β.

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Solution

f(x) = x2 - x - 12 is the given polynomial.
It is given that,α and β are the zeros of the polynomial.
α+β=-ba=--11=1 and αβ=-121=-12
Let 2α and 2β be the zeros of the polynomial g(x).
Thus,
Sum of roots = 2α and 2β = 2(α + β) = (2 × 1) = 2
Product of roots = 2α × 2β = 4αβ = 4(-12) = - 48
Now,
The required polynomial g(x) = x2 - (Sum of roots)x + Product of roots
= x2 - (2)x - 48
= x2 - 2x - 48
Hence, the required polynomial is g(x) = x2 - 2x - 48.

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