Correct option is A)
x3−6x2−x+30
Here,
a=1 , b = -6, c = −1 ,d = 30
∵α,β,γ are zeroes of given polynomial.
∴α+β+γ =−ba=61=6
α.β.γ =−da=−301=−30
αβ+βγ+γα =ca=−11=−1
If α,β,γ are the zeros of the polynomial x3−6x2−x+30 then (αβ+βγ+γα) = ?
(a) -1 (b) 1 (c) -5 (d) 30
If α, β, γ be the zeros of the polynomial p(x) such that α + β + γ = 3, αβ + βγ + γα = -10 and αβγ =24, then p(x) is