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Question

If α, β, γ are the zeros of the polynomial x3 − 6x2 − x + 30, then the value of (αβ + βγ + γα) is

(a) −1
(b) 1
(c) −5
(d) 30

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Solution

Correct option is A)

x36x2x+30

Here,

a=1 , b = -6, c = −1 ,d = 30

∵α,β,γ are zeroes of given polynomial.

∴α+β+γ =ba=61=6

α.β.γ =da=301=30


αβ+βγ+γα =ca=11=1


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