If area of cross section of one end of tube is $8$ cm and velocity of liquid flow is $1.5 m s^{- 1}$ . What is the speed of ejection of the liquid if the life area of cross reaction of the other end is $4.0$ cm.

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Solution

Using $A_{1} v_{1} = A_{2} v_{2}$
Or $8 \times 1.5 = 4 \times v_{2}$
$⟹ v_{2} = 3 m / s$

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