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Question

If arg (¯z1)=arg(¯z2), then

A
z2=kz11(k>0)
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B
z2=kz1(k>0)
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C
|z2|=|¯z1|
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D
None of these
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Solution

The correct option is A z2=kz11(k>0)
arg(¯z1)=arg(¯z2)arg(z1)+arg(z2)=0z1z2=k


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