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Byju's Answer
Standard XIII
Mathematics
Properties of Argument
If arg z < 0,...
Question
If
a
r
g
(
z
)
<
0
, then
a
r
g
(
−
z
)
−
a
r
g
(
z
)
equals
A
π
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B
−
π
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C
−
π
2
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D
π
2
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Solution
The correct option is
A
π
a
r
g
(
z
1
z
2
)
=
a
r
g
(
z
1
)
−
a
r
g
(
z
2
)
∴
a
r
g
(
−
z
)
−
a
r
g
(
z
)
=
a
r
g
(
−
z
z
)
=
a
r
g
(
−
1
)
=
π
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0
Similar questions
Q.
If
a
r
g
(
z
)
<
0
, then
a
r
g
(
−
z
)
−
a
r
g
(
z
)
=
Q.
If arg
z
<
0
, then
a
r
g
(
−
z
)
−
a
r
g
(
z
)
is equal to
Q.
If
arg
(
9
z
)
<
0
, then
a
r
g
(
−
z
)
−
a
r
g
(
z
)
=
Q.
If
z
is a non-zero complex number, then
a
r
g
(
z
)
+
a
r
g
(
¯
¯
¯
z
)
equals
Q.
Let
z
=
1
+
i
b
=
(
a
,
b
)
be any complex number,
a
,
b
,
ϵ
R
and
√
−
1
=
i
.
Let
z
≠
0
+
0
i
,
a
r
g
z
=
tan
−
1
(
I
m
z
R
e
z
)
where
−
π
<
a
r
g
z
≤
π
a
r
g
(
¯
z
)
+
a
r
g
(
−
z
)
=
{
π
,
i
f
a
r
g
(
z
)
<
0
−
π
,
i
f
a
r
g
(
z
)
>
0
Let
z
&
w
be non-zero complex numbers such that they have equal modulus values and
a
r
g
z
−
a
r
g
¯
w
=
π
,
then z equals
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