CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If arg(z1) = 11 π18 and arg (z2) = 19 π18, then the principal argument of z1z2 is


A

(-5 π)/3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

(7 π)/3

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

(-π)/3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

(-π)/3


arg(z1z2) = arg(z1) + arg(z2) + 2kπ [k=0,1, or -1]

= 11π18 + 19π18 + 2kπ

= 30π18 + 2kπ = 5π3 + 2kπ

If k = -1,

Arg(z1z2) = 5π3 - 2π

= π3.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
De Moivre's Theorem
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon