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Question

If arg z3/8=12arg(z2+¯z z), then |z|=

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Solution

The correct option is A 1
arg (z2+¯z z)=2argz3/8=argz3/4
arg arg(z2+¯zzz3/4)=0,z5/4+¯z.z1/4=λR
with z = reiθ,theimaginary part gives
r5/4sin5θ4r34sin5θ4=0
r=1

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