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Byju's Answer
Standard XII
Mathematics
Geometrical Representation of a Complex Number
If Arg z + ...
Question
If Arg
(
z
+
i
)
−
Arg
(
z
−
i
)
=
π
2
, then
z
lies on a ..........
A
Circle
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B
Line
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C
Coordinate axes
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D
None of these
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Solution
The correct option is
A
Circle
Putting z = x+iy,
t
a
n
−
1
y
+
1
x
-
t
a
n
−
1
y
−
1
x
=
π
/2
⇒
1 + (
y
+
1
x
)
(
y
−
1
x
) = 0
⇒
x
2
+
y
2
= 1
It is a circle of center coinciding with origin and radius 1 units.
Hence, option A is correct.
Suggest Corrections
0
Similar questions
Q.
If Arg
(
z
+
i
)
−
Arg
(
z
−
i
)
=
π
2
, then
z
lies on a circle.
If statement is True, enter
1
, else enter
0
Q.
Assertion :If
z
=
√
3
+
4
i
+
√
−
3
+
4
i
, then principal arg of z i.e. arg (z) are
±
π
4
,
±
3
π
4
where
√
−
1
=
i
. Reason: If z = A + iB, then
√
z
=
⎧
⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪
⎨
⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪
⎩
√
|
z
|
+
R
e
(
z
)
2
+
i
√
|
z
|
−
R
e
(
z
)
2
,
if
B
>
0
⎷
|
z
|
+
R
e
(
z
)
2
−
i
√
|
z
|
−
R
e
(
z
)
2
,
if
B
<
0
Q.
If
z
=
1
+
i
√
3
, then
|
a
r
g
(
z
)
|
+
|
a
r
g
(
¯
z
)
|
=
Q.
Given that
|
z
−
1
|
=
1
, where
z
is a non zero point on the complex plane, then
z
−
2
z
is equal to :
Q.
Locus of
z
, if
arg
[
z
−
(
1
+
i
)
]
=
⎧
⎪ ⎪
⎨
⎪ ⎪
⎩
3
π
4
w
h
e
n
|
z
|
≤
|
z
−
2
|
−
π
4
w
h
e
n
|
z
|
>
|
z
−
4
|
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