If at 298 K the bond energies of C - H, C - C, C=C and H - H bonds are respectively 414, 347, 615 and 435 kJ mol−1, the value of enthalpy change for the reaction
-125 kJ
CH2=CH2(g)+H2(g)→CH3−CH3Enthalpy change = Bond energy of raeactants -Bond energy of products.ΔH=1(C=C)+4(C−H)+1(H−H)−1(C−C)−6(C−H)=1(C=C)+1(H−H)−1(C−C)−2(C−H)=615+435−347−2×414=1050−1175=−125kJ.