Question

If atomic radius of F is $x{A}^{\circ }$ then atomic radius of Ne could be :

• A. $<x{A}^{\circ }$
• B. $>x{A}^{\circ }$
• C. $=x{A}^{\circ }$
• D. half of $F$

Answer 1

Answer: (B)

$>x{A}^{\circ }$

Noble gases have maximum atomic radii in a particular period as it has Van der Waal's radius. Van der Waal's radius is largest.

So, the radius of Ne is greater than that of F, therefore, the radius of $Ne>x{A}^o$.