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Question

If ax2+2bx+3c=0,aā‰ 0,c>0 does not have any real roots, then which of the following is/are true?

A
4a4b+3c>0
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B
a+6b+27c>0
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C
4a4b+3c<0
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D
a+6b+27c<0
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Solution

The correct option is B a+6b+27c>0
Let f(x)=ax2+2bx+3c
Now, f(x)=0 does not have real root,
Checking f(0)=3c>0, so
f(x)>0 xR

Now,
f(2)>04a4b+3c>0

f(13)>0a9+2b3+3c>0a+6b+27c>0

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