If ax2+2bx+c=0,a≠0 and dx2+2ex+f=0,d≠0 have a common root and a,b,c are in G.P., then da,eb,fc are in
A
A.P.
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B
G.P.
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C
H.P.
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D
None of these
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Solution
The correct option is A A.P. Given : a,b,c are in G.P., so b2=ac
Now, ax2+2bx+c=0
Checking the discriminant, we get D=4b2−4ac=0(∵b2=ac)
This quadratic equation has real and equal roots, let it be α
Sum of roots 2α=−2ba⇒α=−ba
Thus dx2+2ex+f=0 has one root as α dα2+2eα+f=0⇒db2a2−2eba+f=0⇒db2+fa2=2eab
Dividing by ab2, we get ⇒da+fab2=2eb∴da+fc=2eb(∵b2=ac)