Question

If $a{x}^2+2hxy+b{y}^2+2gx+2fy+c=0$ then $\frac{dy}{dx}=$

• A. $-(\frac{ax+hy+g}{hx+by+f})$
• B. $-(\frac{ax+hy+g}{bx+hy+f})$
• C. $-(\frac{hx+by+f}{ax+hy+g})$
• D. $-(\frac{hx+by+f}{hx+ay+g})$

Answer 1

The correct option is A $-(\frac{ax+hy+g}{hx+by+f})$

Given: $a{x}^2+2hxy+b{y}^2+2gx+2fy+c=0$

$2ax+2hy+2hx\frac{dy}{dx}+2by\frac{dy}{dx}+2g+2f\frac{dy}{dx}=0$
$\frac{-(2ax+2hy+2g)}{2hx+2by+2f}=\frac{dy}{dx}$