If ax2+bx+c=0 and bx2+cx+a=0 have a common root
a ≠ 0, then a3+b3+c3abc=
1
2
3
4
The condition for common roots gives (bc−a2)2=(ca−b2)(ab−c2) On simplification gives a3+b3+c3=3abc
If ax2+bx+c=0 and bx2+cx+a=0 have a common root and a,b,c are non - zero real numbers thena3+b3+c3abc is equal to :