Question

If $a{x}^2$ +bx+c=0 has no real roots and a+b+c<0, then

• A. c 0
• B. c < 0
• C. c > 0
• D. c = 0

Answer 1

The correct option is B

c < 0

f(X) = $a{x}^2+bx+c$ f(1) = a +b +c < 0

$\therefore$ f(0) $<$ 0 $\Rightarrow$ c < 0