If ax2+bx+c has positive roots then a>0, b>0 and c>0.
True
False
Take 2 positive roots, say 3 & 2 and substitute it in the equation.Their polynomial form will be x2−5x+6. Hence the statement is false.
If a > 0, b > 0, c > 0 are positive read numbers in AP. If ax2+bx+c=0 has real roots then
If ax2 +bx+c=0 has no real roots and a+b+c<0, then
If a, b, c ∈ R and a ≠ 0, c < 0, and if the quadratic equation ax2+bx+c = 0 has imaginary roots, then a + b + c is