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Question

If ax4+bx3+cx2+dx+e=∣ ∣x3+3xx1x+3x+12xx4x3x+43x∣ ∣, then e =

A
1
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B
0
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C
2
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D
-1
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Solution

The correct option is C 0
We have,
ax4+bx3+cx2+dx+e=∣ ∣x3+3xx1x+3x+12xx4x3x+43x∣ ∣
Substitute x=0 both sides,

a(0)+b(0)+c(0)+d(0)+e=∣ ∣013104340∣ ∣

e=0+1(012)+3(40)=12+12=0, expand the determinant along first row.

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