If ax+b=0 is a linear equation and a≠0 then value of x=...........
Here,
ax+b=0 and a≠0
⇒ Subtracting b on both sides,
ax+b-b=0-bax=-b
Dividing a on both sides,
axa=-ba
x=-ba
Therefore, the value of x=-ba
If aandb are the roots of the equation x2+ax+b=0,a≠0,b≠0, the values of aandb are respectively