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Question

If ax +by + cz = p, then minimum value of x2+y2+z2 is

A
(pa+b+c)2
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B
p2a2+b2+c2
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C
a2+b2+c2p2
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D
(a+b+cp)2
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Solution

The correct option is C p2a2+b2+c2
Given ax+by+cz=p
(ax+by+cz)2(a2+b2+c2)(x2+y2+z2)x2+y2+z2(ax+by+cza2+b2+c2)2
x2+y2+z2(p2a2+b2+c2)

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