If $a x^{n} + b x^{n - 1} + c = 0$ is a quadratic equation, then must be equal to

0.0

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Solution

The correct option is C 2
Given that $a x^{n} + b x^{(n - 1)} + c = 0$ is a quadratic equation.
The standard form of a quadratic equation is given by
$a x^{2} + b x + c = 0,$ where $a, b$ and $c$ are real numbers and $a \neq 0.$
Thus, on comparison, we have $n = 2.$

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If axn+bxn−1+c=0 is a quadratic equation, then must be equal to

The correct option is C 2Given that axn+bx(n−1)+c=0 is a quadratic equation. The standard form of a quadratic equation is given by ax2+bx+c=0, where a,b and c are real numbers and a≠0. Thus, on comparison, we have n=2.

If $a x^{n} + b x^{n - 1} + c = 0$ is a quadratic equation, then must be equal to

The correct option is C 2
Given that $a x^{n} + b x^{(n - 1)} + c = 0$ is a quadratic equation.
The standard form of a quadratic equation is given by
$a x^{2} + b x + c = 0,$ where $a, b$ and $c$ are real numbers and $a \neq 0.$
Thus, on comparison, we have $n = 2.$