Question

If $a{x}^n+b{x}^{n-1}+c=0$ is a quadratic equation, then $n=$.

• A. 0.0
• B. 1
• C. 2

Answer 1

The correct option is C 2

Given that $a{x}^n+b{x}^{(n-1)}+c=0$ is a quadratic equation.
The standard form of a quadratic equation is given by
$a{x}^2+bx+c=0,$ where $a,b$ and $c$ are constants and $a\ne 0.$
Thus, on comparison, we have $n=2.$