If a x2-b x-c-ax-p2 then prove that b2-4 ac

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Nature of Roots

If a x2+b x+c...

Question

If ax²+ bx +c = a(x - p)² then prove that b² = 4ac

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b x^{2} - 2 \sqrt{a c} x + b = 0

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(a + b + c)^{2} - b^{2} - 4 a c

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a x^{2} + 2 b x + c = 0

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\frac{b^{2} - a c}{B^{2} - A C} = {(\frac{a}{A})}^{2}

a x^{2} + b x + c = 0

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