If b1b2=2(c1+c2), then at least one of the equations x2+b1x+c1=0 and x2+b2x+c2=0 has
A
Imaginary roots.
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B
Real roots.
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C
Purely Imaginary roots.
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D
None of the above.
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Solution
The correct option is C Real roots. b1b2=2(c1+c2)x2+b1x+c1=0D1=b12−4c1x2+b2x+c2=0D2=b22−4c2D1+D2=b12−4c1+b22−4c2=b12+b22−4(c1+c2)=b12+b22−2b1b2=(b1−b2)2∴D1+D2≥0